--[params]
-- string :username
-- int :min_days = 10
WITH consecutive_visits AS (
SELECT user_id,
visited_at,
-- s 的值对于连续日期组将是相同的
visited_at - (DENSE_RANK() OVER (PARTITION BY user_id ORDER BY visited_at))::int s
FROM user_visits
WHERE user_id = (SELECT id FROM users WHERE username = :username)
)
SELECT
MIN(visited_at) period_start,
COUNT(*) AS consecutive_days,
MAX(visited_at) period_end
FROM consecutive_visits
GROUP BY user_id, s
HAVING COUNT(*) >= :min_days
ORDER BY period_start DESC
我在开启安全模式(仅限官方插件)的情况下尝试了,但问题依旧存在。