# Get list of invited users

**URL:** <https://meta.discourse.org/t/get-list-of-invited-users/64184>\
**Category:** Feature\
**Tags:** invites\
**Created:** [2017 年6 月 8 日 18:48 UTC](https://meta.discourse.org/t/get-list-of-invited-users/64184 "2017-06-08T18:48:05Z")\
**Posts on this page:** 1\
**Showing post:** 3

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作者： ![techAPJ](https://sea3.discourse-cdn.com/meta/user_avatar/meta.discourse.org/techapj/32/342990_2.png) [@techAPJ](https://meta.discourse.org/u/techAPJ)\
发布日期： [2017 年6 月 8 日 19:30 UTC](https://meta.discourse.org/t/get-list-of-invited-users/64184/3 "2017-06-08T19:30:45Z")

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> [@pfaffman](#):
>
> Is there a way to do this? (Other than [data explorer](https://meta.discourse.org/t/32566?silent=true)?)

What’s the issue with using [data explorer](https://meta.discourse.org/t/32566?silent=true)? A simple [data explorer](https://meta.discourse.org/t/32566?silent=true) query for this will list all the invited users in properly formatted (hyperlinked) UI and the result can be exported as needed.

Here is the [data explorer](https://meta.discourse.org/t/32566?silent=true) query if you are interested:

```plaintext
SELECT user_id,
       invited_by_id as invited_by_user_id,
       redeemed_at
FROM invites
WHERE redeemed_at IS NOT NULL
ORDER BY redeemed_at DESC

```

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_[View the full topic](https://meta.discourse.org/t/get-list-of-invited-users/64184)._