你好,我决定为此开启一个新话题:
过去六个月的优质用户
对于“过去六个月的优质用户”,我使用了 查询的第二个版本。
我添加了用户名以及一个 :limit 参数。
-- [params]
-- int :limit = 20
SELECT
sum(p.score) / count(p) as "average score per post",
count(p.id) as post_count,
-- p.user_id,
u.username
FROM posts p
JOIN users u ON u.id = p.user_id
WHERE p.created_at >= CURRENT_DATE - INTERVAL '6 month'
AND NOT u.admin
AND u.active
GROUP by user_id, u.views, u.username
HAVING count(p.id) > 50
ORDER BY sum(p.score) / count(p) DESC
LIMIT :limit
前 50 名发帖用户
对于“前 50 名发帖用户”的查询,我使用了 这个版本,并添加了 limit 参数以及你需要的用户名。
-- [params]
-- int :months_ago = 1
-- int :limit = 50
WITH query_period AS (
SELECT
date_trunc('month', CURRENT_DATE) - INTERVAL ':months_ago months' as period_start,
date_trunc('month', CURRENT_DATE) - INTERVAL ':months_ago months' + INTERVAL '1 month' - INTERVAL '1 second' as period_end
),
user_posts_in_period AS (
SELECT
p.user_id, u.username
FROM users u, posts p
INNER JOIN query_period qp
ON p.created_at >= qp.period_start
AND p.created_at <= qp.period_end
WHERE p.user_id > 0
AND u.id = p.user_id
)
SELECT
up.username,
-- up.user_id,
count(1) as post_count
FROM user_posts_in_period up
GROUP BY up.user_id, up.username
ORDER BY post_count DESC
LIMIT :limit
请告诉我是否符合你的需求。
此致