从数据库日志中,我们发现由 user.rb#L379 生成的子查询中存在一些不必要的 ORDER BY。其中一个示例如下:
SELECT
"group_users"."group_id"
FROM
"group_users"
WHERE
"group_users"."group_id" IN (
SELECT
"groups"."id"
FROM
"groups"
WHERE
(groups.id > 0)
ORDER BY
name ASC
)
AND "group_users"."user_id" = 762
子查询中的 ORDER BY 毫无意义,移除它可以加速查询。根据我们的测试,这可以将查询性能提升 18% 至 90%(具体取决于子查询中排序所浪费的时间)。
SELECT
DISTINCT users.id
FROM
"users" CROSS
JOIN tags t
LEFT JOIN tag_users tu ON users.id = tu.user_id
AND t.id = tu.tag_id
WHERE
(
t.id IN (1825)
AND tu.notification_level IS NULL
)
从数据库日志中我们发现了一条由 group.rb#L112 生成的慢查询(耗时 6064379 纳秒),该查询包含多个子查询和 UNION 操作,内容如下:
SELECT
"groups"."id",
"groups"."name"
FROM
"groups"
INNER JOIN "group_users" ON "groups"."id" = "group_users"."group_id"
WHERE
"group_users"."user_id" = 296
AND (groups.id > 0)
AND (
groups.id IN (
SELECT
id
FROM
groups
WHERE
visibility_level = 0
UNION ALL
SELECT
id
FROM
groups
WHERE
visibility_level = 1
AND 296 IS NOT NULL
UNION ALL
SELECT
g.id
FROM
groups g
JOIN group_users gu ON gu.group_id = g.id
AND gu.user_id = 296
WHERE
g.visibility_level = 2
UNION ALL
SELECT
g.id
FROM
groups g
LEFT JOIN group_users gu ON gu.group_id = g.id
AND gu.user_id = 296
AND gu.owner
WHERE
g.visibility_level = 3
AND (
gu.id IS NOT NULL
OR FALSE
)
UNION ALL
SELECT
g.id
FROM
groups g
JOIN group_users gu ON gu.group_id = g.id
AND gu.user_id = 296
AND gu.owner
WHERE
g.visibility_level = 4
)
)
ORDER BY
name ASC
显然,该查询等价于以下查询:
SELECT
"groups"."id",
"groups"."name"
FROM
"groups"
INNER JOIN "group_users" ON "groups"."id" = "group_users"."group_id"
WHERE
"group_users"."user_id" = 296 AND
groups.visibility_level IN (0, 1, 2, 3, 4)
ORDER BY
name ASC
SELECT
"groups"."id",
"groups"."name"
FROM
"groups"
INNER JOIN "group_users" gu ON "groups"."id" = gu."group_id"
WHERE
"group_users"."user_id" = 296
AND (groups.id > 0)
AND (
groups.visibility_level IN (0, 1, 2)
OR (groups.visibility_level IN (3,4) and gu.owner)
)
ORDER BY
name ASC
包含谓词 visibility_level = 0,1,2 的子查询可替换为 groups.visibility_level IN (0, 1, 2),包含谓词 visibility_level = 3,4 的子查询可替换为 or (groups.visibility_level IN (3,4) and gu.owner)。
SELECT
COUNT(DISTINCT "directory_items"."id")
FROM
"directory_items"
LEFT OUTER JOIN "users" ON "users"."id" = "directory_items"."user_id"
LEFT OUTER JOIN "group_users" ON "group_users"."user_id" = "users"."id"
LEFT OUTER JOIN "groups" ON "groups"."id" = "group_users"."group_id"
LEFT OUTER JOIN "user_stats" ON "user_stats"."user_id" = "directory_items"."user_id"
WHERE
"directory_items"."period_type" = 1
AND "groups"."id" = 2898
SELECT
COUNT("directory_items"."id")
FROM
"directory_items"
LEFT OUTER JOIN "users" ON "users"."id" = "directory_items"."user_id"
LEFT OUTER JOIN "group_users" ON "group_users"."user_id" = "users"."id"
WHERE
"directory_items"."period_type" = 1
AND "group_users"."group_id" = 2898
SELECT
COUNT(*)
FROM
"badges"
INNER JOIN "user_badges" ON "badges"."id" = "user_badges"."badge_id"
WHERE
"user_badges"."user_id" = 2112
AND (
user_badges.badge_id IN (
SELECT
id
FROM
badges
WHERE
enabled
)
)
AND "badges"."id" = 1
该子查询可以替换为简单的谓词 badges.enabled,如下所示:
SELECT
COUNT(*)
FROM
"badges"
INNER JOIN "user_badges" ON "badges"."id" = "user_badges"."badge_id"
WHERE
"user_badges"."user_id" = 2112
AND badges.enabled
AND "badges"."id" = 1