用户统计信息加电子邮件

数据与报告
1

如何在此基础上添加“阅读时长”、“帖子阅读数”和“用户访问次数”列？

本质上，我想将以下查询与您在此处发布的查询结合起来，并添加“阅读时长”（如果可能）：

select user_id,
    count(1) as visits,
    sum(posts_read) as posts_read
from user_visits
where posts_read > 0
and visited_at > CURRENT_TIMESTAMP - INTERVAL '7 days'
group by user_id
order by visits desc, posts_read desc

注意：我更喜欢能够像您查询中那样定义间隔参数，但希望将我发布的查询中的用户显示为完整的电子邮件地址（而不仅仅是电子邮件域）。

我刚开始尝试编写查询，并且理解参数，也能够修改您的查询以显示完整的电子邮件地址。我只是无法将我共享的查询中的 visits 和 posts_read 列合并进来，也无法添加阅读时长。

2 个赞
2

我认为按用户而不是按电子邮件域分组显示结果会使此查询略有不同。让我们将此分成一个单独的主题。:+1:

1 个赞
3

我认为这样做应该可以：

-- [params]
-- string :interval = 7 days

WITH post_data AS (

    SELECT
        p.user_id,
        COUNT(p.id) AS total_posts,
        COUNT(p.id) FILTER (WHERE p.post_number = 1 AND t.archetype = 'regular') AS topics,
        COUNT(p.id) FILTER (WHERE p.post_number > 1 AND t.archetype = 'regular') AS posts,
        COUNT(p.id) FILTER (WHERE t.archetype = 'private_message') AS pms
    FROM posts p
      JOIN topics t ON t.id = p.topic_id
    WHERE p.created_at >= CURRENT_DATE - INTERVAL :interval 
      AND p.user_id > 0 
      AND p.deleted_at ISNULL
      AND t.deleted_at ISNULL
      AND p.post_type <> 3
GROUP BY p.user_id

    ),
    
user_data AS (
    
    SELECT 
        uv.user_id,
        COUNT(*) AS visits,
        SUM(posts_read) AS posts_read,
        SUM(time_read)/60 AS time_read
    FROM user_visits uv
    WHERE uv.visited_at >= CURRENT_DATE - INTERVAL :interval
    GROUP BY uv.user_id
    )

SELECT 
    ud.user_id,
    ue.email,
    ud.visits,
    ud.posts_read,
    ud.time_read,
    pd.total_posts,
    pd.topics,
    pd.posts,
    pd.pms
FROM user_data ud 
  LEFT JOIN post_data pd ON pd.user_id = ud.user_id
  JOIN user_emails ue ON ue.user_id = ud.user_id AND ue.primary = TRUE
ORDER BY ud.posts_read DESC
1 个赞
4

太棒了！！非常感谢您。

1 个赞