Devo effettuare la richiesta per anno. Come input… ad esempio dal 2019-01-01 al 2019-12-31
Numero di risposte per categoria (TOPIC e POST)
I tag più popolari in un anno
Numero medio di nuovi topic al mese (l'ho trovato nel pannello di amministrazione del rapporto amministrativo)
Numero medio di risposte al mese
Numero medio di nuovi utenti al mese
Qualcuno può darmi una mano con questo??? O darmi qualche indicazione
Prima di impostare altre query, confermatemi se è questo che vi serve:
WITH data AS (SELECT
id,
EXTRACT(MONTH FROM created_at) AS month,
EXTRACT(YEAR FROM created_at) AS year
FROM topics)
SELECT
ROUND(AVG(qt_topic_month)) AS avg_topic,
year
FROM
(SELECT COUNT(id) AS qt_topic_month,
month,
year
FROM data
GROUP BY month, year) AS top_m
GROUP BY year
ORDER BY year DESC
Nessun problema, credo che queste siano le informazioni che stai cercando:
WITH data AS (SELECT
id,
EXTRACT(DAY FROM created_at) AS day,
EXTRACT(MONTH FROM created_at) AS month,
EXTRACT(YEAR FROM created_at) AS year
FROM topics)
SELECT
year,
month,
ROUND(AVG(qt_topic_day)) AS avg_topic
FROM
(SELECT COUNT(id) AS qt_topic_day,
day,
month,
year
FROM data
GROUP BY day, month, year) AS top_day
GROUP BY month, year
ORDER BY year DESC, month ASC
Scusa per il ritardo nella risposta. Di seguito le query richieste; poiché alcune sono più complesse del solito, resto a tua disposizione per eventuali chiarimenti.
Michelle
WITH post AS (SELECT
id AS post_id,
topic_id,
EXTRACT(YEAR FROM created_at) AS year
FROM posts
WHERE post_type = 1
AND deleted_at IS NULL
AND post_number != 1)
SELECT
p.year,
t.category_id AS id,
c.name AS category,
COUNT(p.post_id) AS qt
FROM post p
INNER JOIN topics t ON t.id = p.topic_id
LEFT JOIN categories c ON c.id = t.category_id
WHERE t.deleted_at IS NULL
-- AND t.category_id IS NOT NULL --> *** Abilita per eliminare post senza categoria ***
GROUP BY t.category_id, c.name, p.year
ORDER BY p.year DESC, qt DESC
year
id
category
qt
2020
13
Generale
14
2020
16
Knowledge Base
3
2020
15
Staff
3
2020
1
Non categorizzato
2
2020
17
Idee
1
2019
18
Builds
10
2019
1
Non categorizzato
8
2019
11
CS001x: Introduzione all’informatica
7
2019
13
Generale
5
WITH data AS (SELECT
tag_id,
EXTRACT(YEAR FROM created_at) AS year
FROM topic_tags)
SELECT year, rank, name, qt FROM (
SELECT
tag_id,
COUNT(tag_id) AS qt,
year,
rank() OVER (PARTITION BY year ORDER BY COUNT(tag_id) DESC) AS rank
FROM
data
GROUP BY year, tag_id) as rnk
INNER JOIN tags ON tags.id = rnk.tag_id
WHERE rank <= 5 -- *** Scegli il limite di classificazione ***
ORDER BY year DESC, qt DESC
year
rank
tag_name
quantity
2020
1
featured
7
2020
2
human-resources
3
2020
3
demo
1
2019
1
demo
12
2019
2
human-resources
4
2019
3
featured
3
2019
3
customer
3
2019
3
milestones-2019
3
WITH data AS (SELECT
id,
EXTRACT(DAY FROM created_at) AS day,
EXTRACT(MONTH FROM created_at) AS month,
EXTRACT(YEAR FROM created_at) AS year
FROM topics
WHERE deleted_at IS NULL)
SELECT
year,
month,
ROUND(AVG(qt_topic_day)) AS avg_topic_by_day
FROM
(SELECT COUNT(id) AS qt_topic_day,
day,
month,
year
FROM data
GROUP BY day, month, year) AS top_day
GROUP BY month, year
ORDER BY year DESC, month ASC
year
month
avg_topic_by_day
2020
1
1
2020
2
1
2020
3
2
2020
4
3
2020
5
2
2019
4
9
2019
5
4
2019
6
4
2019
7
1
2019
8
2
2019
9
3
2019
10
1
WITH data AS (SELECT
id,
EXTRACT(DAY FROM created_at) AS day,
EXTRACT(MONTH FROM created_at) AS month,
EXTRACT(YEAR FROM created_at) AS year
FROM posts
WHERE post_type = 1
AND deleted_at IS NULL
AND post_number != 1)
SELECT
year,
month,
ROUND(AVG(qt_reply_day)) AS avg_reply_by_day
FROM
(SELECT COUNT(id) AS qt_reply_day,
day,
month,
year
FROM data
GROUP BY day, month, year) AS top_reply
GROUP BY month, year
ORDER BY year DESC, month ASC
year
month
avg_reply_by_day
2020
1
7
2020
3
2
2020
4
5
2020
5
6
2019
4
3
2019
5
2
2019
6
4
2019
7
2
2019
8
15
2019
9
3
2019
10
5
2019
12
2
WITH data AS (SELECT
id,
EXTRACT(DAY FROM created_at) AS day,
EXTRACT(MONTH FROM created_at) AS month,
EXTRACT(YEAR FROM created_at) AS year
FROM users)
SELECT
year,
month,
ROUND(AVG(qt_new_user)) AS avg_new_user_by_day
FROM
(SELECT COUNT(id) AS qt_new_user,
day,
month,
year
FROM data
GROUP BY day, month, year) AS top_new_user
GROUP BY month, year
ORDER BY year DESC, month ASC