Immaginiamo che in un mese ci siano 100 soluzioni. Ci sono venti persone che appartengono a un determinato gruppo e hanno iniziato a contrassegnare le loro risposte come soluzioni, per un totale di venti. Desidero avere una query in cui specificherò lâID del gruppo principale nello script e recupererò i dati per mese, mostrando per questo mese 20/100 - 20%.
Ho cercato di rendere le query piĂš dettagliate, per facilitarne la comprensione e la manutenzione in futuro.
WITH users_groups AS (
SELECT
user_id,
g.id,
g.name AS group_name
FROM users u
INNER JOIN user_actions ua ON ua.user_id = u.id
LEFT JOIN groups g ON g.id = u.primary_group_id
WHERE ua.action_type = 15
GROUP BY user_id, g.id
),
tt_solution_by_month AS (
SELECT
date_part('year', created_at) AS year,
date_part('month', created_at) AS month,
COUNT(*) AS "total"
FROM user_actions ua
WHERE ua.action_type = 15
GROUP BY date_part('year', created_at), date_part('month', created_at)
ORDER BY date_part('year', created_at) ASC, date_part('month', created_at)
),
tt_solution_groups_by_month AS (
SELECT
date_part('year', created_at) AS year,
date_part('month', created_at) AS month,
ug.group_name,
COUNT(*) AS "tt_groups"
FROM user_actions ua
INNER JOIN users_groups ug ON ug.user_id = ua.user_id
WHERE ua.action_type = 15
GROUP BY ug.group_name, date_part('year', created_at), date_part('month', created_at)
ORDER BY date_part('year', created_at) ASC, date_part('month', created_at), ug.group_name)
SELECT
ts.year,
ts.month,
COALESCE(tsg.group_name,'senza gruppo'),
tt_groups,
total,
TRUNC((tt_groups::decimal/total::decimal) *100,1) AS "%"
FROM tt_solution_groups_by_month tsg
INNER JOIN tt_solution_by_month ts
ON ts.year = tsg.year AND ts.month = tsg.month
Fammi sapere se questo è il risultato che ti aspetti o se devo apportare delle modifiche.
Quasi perfetto! Non mi servono le colonne tt_groups e total, solo il numero percentuale. Per quanto riguarda la colonna group_name, la query sarà per un solo gruppo, quindi non serve nemmeno quella colonna. Nel codice della query specificherò semplicemente primary_group_id, cosÏ cercherà le soluzioni solo per questo gruppo esatto.
-- [params]
-- string :primary_group_id
WITH users_groups AS (
SELECT
user_id,
g.id,
g.name AS group_name
FROM users u
INNER JOIN user_actions ua ON ua.user_id = u.id
LEFT JOIN groups g ON g.id = u.primary_group_id
WHERE ua.action_type = 15
AND u.primary_group_id = :primary_group_id
GROUP BY user_id, g.id
),
tt_solution_by_month AS (
SELECT
date_part('year', created_at) AS year,
date_part('month', created_at) AS month,
COUNT(*) AS "total"
FROM user_actions ua
WHERE ua.action_type = 15
GROUP BY date_part('year', created_at), date_part('month', created_at)
ORDER BY date_part('year', created_at) ASC, date_part('month', created_at)
),
tt_solution_groups_by_month AS (
SELECT
date_part('year', created_at) AS year,
date_part('month', created_at) AS month,
ug.group_name,
COUNT(*) AS "tt_groups"
FROM user_actions ua
INNER JOIN users_groups ug ON ug.user_id = ua.user_id
WHERE ua.action_type = 15
GROUP BY ug.group_name, date_part('year', created_at), date_part('month', created_at)
ORDER BY date_part('year', created_at) ASC, date_part('month', created_at), ug.group_name)
SELECT
ts.year,
ts.month,
TRUNC((tt_groups::decimal/total::decimal) *100,1) AS "%"
FROM tt_solution_groups_by_month tsg
INNER JOIN tt_solution_by_month ts
ON ts.year = tsg.year AND ts.month = tsg.month