大家好,
您是否知道数据探索器查询,可以帮助查看在特定时间段内员工帖子/主题的数量和百分比?
感谢您的所有帮助。
大家好,
您是否知道数据探索器查询,可以帮助查看在特定时间段内员工帖子/主题的数量和百分比?
感谢您的所有帮助。
希望以下查询能帮助您。
--[params]
--date :start_date
--date :end_date
WITH posts_data AS (
SELECT
COUNT(*) AS total_posts,
SUM(CASE
WHEN u.admin = 't' OR u.moderator = 't' THEN 1
ELSE 0
END) AS staff_posts
FROM posts p
INNER JOIN users u ON u.id = p.user_id
WHERE p. post_type = 1
AND p.deleted_at ISNULL
AND p.created_at BETWEEN :start_date AND :end_date
AND p.user_id > 0
)
SELECT
total_posts,
staff_posts,
ROUND((staff_posts/total_posts::decimal)*100,2) "staff_posts %"
FROM posts_data
| total_posts | staff_posts | staff_posts % |
|---|---|---|
| 7400 | 3108 | 42.0 |
您好 @michebs,
感谢您的分享。请问我们能否将此功能应用于我们自己创建的特定群组?
比如说,我们有一个员工群组,但并非所有员工都是版主或管理员,因此我们需要创建一个名为“Katalon_team”的新群组,我们能否获取该 Katalon 团队中所有人员的数据?
谢谢。
我调整了查询,并将组名添加为输入参数,这样它就可以适用于任何组。希望对您有帮助。
--[params]
--date :start_date = 2022-01-01
--date :end_date = 2023-01-01
--string :group_name = staff
WITH group_filter AS (
SELECT user_id FROM group_users gu
JOIN groups g ON g.id = gu.group_id
WHERE LOWER(g.name) LIKE '%'||:group_name||'%'
),
posts_data AS (
SELECT
COUNT(*) AS total_posts,
SUM(CASE
WHEN gf.user_id ISNULL THEN 0
ELSE 1
END) AS staff_posts
FROM posts p
LEFT JOIN group_filter gf ON gf.user_id = p.user_id
WHERE p. post_type = 1
AND p.deleted_at ISNULL
AND p.created_at BETWEEN :start_date AND :end_date
AND p.user_id > 0
)
SELECT
total_posts,
staff_posts,
ROUND((staff_posts/total_posts::decimal)*100,2) "staff_posts %"
FROM posts_data
此错误似乎与缺少最后的 SELECT 语句(第 27 行)有关。
SELECT
total_posts,
staff_posts,
ROUND((staff_posts/total_posts::decimal)*100,2) "staff_posts %"
FROM posts_data
这有意义吗?
是的,抱歉是我的错,非常感谢您的帮助。
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